How many moles are in 89 grams of KCI

The number of moles in 89 grams of KCl is approximately 1.193 moles

Explanation:

A mole of an element or compound, is the quantity of the element or compound that contains 6.022 × 10²³ molecules of the element or compound, such that the molar mass of one mole is dependent on the mass of each molecule of the element or compound that make up the 6.022 × 10²³ particles

The given parameters are;

The mass of the KCl = 89 grams

The Molar mass, MW, of potassium, K = 39.1 g/mole

The Molar mass, MW, of chlorine, Cl = 35.5 g/mole

Therefore, given that KCl, has one K and one Cl, per mole, we have;

The Molar mass, MW, of potassium chloride, KCl = (39.1 + 35.5) g/mole = 74.6 g/mole

Therefore, the number of moles of KCl in 89 g, 'n' is given as follows;

n = (89 g)/(74.6 g/mole) ≈ 1.193 moles

The number of moles in 89 grams of KCl, n ≈ 1.193 moles.

mass of KCl = 89 g

MW K = 39.1 g/mol

MW Cl = 35.5 g/mol

moles of KCl

Step 1: Calculate the MW of KCl.

MW KCl = MW K + MW Cl

MW KCl = 39.1 g/mol + 35.5 g/mol

MW KCl = 74.6 g/mol

Step 2: Solve for the number of moles of KCl.

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the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol