Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction. Li(s) Al3 (aq) eCr(s) Al3 (aq) 3e75) A) Li(s) with Al(s) B) Li(s) with Al3 (aq) C) Li (aq) with Al(s) D) Li (aq) with Al3 (aq)

The question is incomplete, the complete question is:

Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction.

A) Li(s) with Al(s)

B) Li(s) with (aq)

C) (aq) with Al(s)

D) (aq) with (aq)

The correct option is B): Li(s) with (aq)

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction.  

The chemical species will undergo a reduction reaction if the value of standard reduction potential is more positive or less negative.

For the given half-reactions:

As the value of standard reduction potential of aluminium is less negative. Thus, it undergoes reduction reaction and lithium will undergo oxidation reaction.

The half-reaction follows:

Oxidation half-reaction:              ( × 3)

Reduction half-reaction:  

Overall cell-reaction:  

Hence, the correct option is B): Li(s) with (aq)

sry but any answer choices

i believe the answer is a.