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Chemistry, 17.06.2021 20:50 CamBroOkaii2590
Determina la cantidad, en masa, de Cu(NO3)2 que podemos obtener, al tratar 25 g de Cu con un exceso de HNO3, si en la reacción obtenemos también NO2 más agua. ( masa atómicas: Cu:63,5 g/mol; N:14 g/mol; O:16 g/mol) Cu + 4 HNO3 ↔ Cu(NO3)2 + 2 NO2 + H2O
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Determina la cantidad, en masa, de Cu(NO3)2 que podemos obtener, al tratar 25 g de Cu con un exceso...
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