What is the mass of 4.76 moles of NazPO4
(gram-formula mass = 164 grams/mole)?

Explanation:

so mass = moles × mr ( mr is 164)

so 4.76 × 164

which is 780.64 g

so to 3 s.f it is 780 g

hope this helps :)

answer; ///i do believe that the correct answer is (b); ///particle composed of two or more atoms bonded together;

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g