Chemistry, 16.06.2021 15:40 mauricestepenson791

Calculate the mass of carbon dioxide produced from 11.2 g of octane, C8H18, in the following reaction: 2C8H18(g) + 25O2(g) -> 16CO2(g) + 18H2O(g).
A. 46.2 g CO2
B. 34.5 g CO2
C. 89.6 g CO2
D. 58.9 g CO2
E. 17.3 g CO2

Answers: 3

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Answers

Answer from: alleshia2007

Explanation:

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Answer from: jkpope06

C H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R Y

Answer from: Quest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be $^{9}_{5}be^{-}$ and $^{9}_{4}be$ .

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.

Answer from: Quest

The answer should be vaporization

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Calculate the mass of carbon dioxide produced from 11.2 g of octane, C8H18, in the following reactio...

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