How many atoms are in 490 moles of barium?

2.95 * 10^23 atoms

Explanation:

The number of atoms in a mole is always equal to Avogadro's constant, which is 6.02214076×10²³ mol⁻¹.

To find the number of atoms in 0.490 moles of barium, multiply it with Avogadro's constant:

0.490 mol * 6.02214076×10²³ mol⁻¹ ≈ 2.9508 * 10^23

Convert to SigFigs (if necessary):

2.95 * 10^23

is there multiple choice answers?