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Chemistry, 11.06.2021 08:30 jfefeferf

You are reacting hydrogen gas with tin oxide to purify tin. SnO2 + 2 H2 → Sn + 2 H2O. You have 45.8L of H2 gas and 351.3g of SnO2. What will be the limiting reactant, and how much of the excess reactant will be left over?

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You are reacting hydrogen gas with tin oxide to purify tin. SnO2 + 2 H2 → Sn + 2 H2O. You have 45.8L...
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