A sealed balloon filled with 5.00 liters of gas has a pressure of 1.49 atm. This balloon is taken under water where the pressure of the gas becomes 7.62 atm. What is the new volume of this gas? (Assume the temperature does not change.)
O 56.7L
0 0.978 L
0 1.02 L
O 2.27L

0.978L

Explanation:

Using Boyle's law equation as follows;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information,

P1 = 1.49 atm

V1 = 5.00 liters

P2 = 7.62 atm

V2 = ?

Using P1V1 = P2V2

1.49 × 5 = 7.62 × V2

7.45 = 7.62V2

V2 = 7.45/7.62

V2 = 0.978L

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.