How many grams of KNO2 would be needed to make 230. mL of a 3.21 M KNO2 solution? If possible, provide work

62.73g

Explanation:

Using the following formula;

Molarity = n/V

Where;

n = number of moles (mol)

V = volume (L)

From the information given below,

V = 230mL = 230/1000 = 0.230L

M = 3.21 M

3.21 = n/0.230

n = 3.21 × 0.230

n = 0.738 mol of KNO2

Molar mass of KNO2 = 39 + 14 + 16(2)

= 53 + 32

= 85g/mol

mole = mass/molar mass

0.738 mol = mass/85g/mol

Mass = 0.738 × 85

mass = 62.73g

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b