Calculate the molarity of a potassium hydroxide solution if 25.0 ml of this solution was completely neutralized by 23.3 ml of 0.506 M sulfuric acid.

0.943 M of potassium hydroxide solution is required.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

To calculate the molarity of potassium hydroxide, the equation used is:

             ........(1)

where,

are the n-factor, molarity and volume of acid that is

are the n-factor, molarity and volume of the base that is KOH

We are given:

Putting values in equation 1, we get:

Hence, 0.943 M of potassium hydroxide solution is required.

h let me think

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml