2 NABr + Ca(OH)2 = CaBr2 + 2 NaOH How many moles of CaB 2 are produced, if 14.72 moles of NaBr and excess Ca(OH) 2 react?

7.36 moles of will be produced.

Explanation:

We are given:

Moles of NaBr = 14.72 moles

The given chemical equation follows:

By the stoichiometry of the reaction:

2 moles of NaBr produces 1 mole of calcium bromide

So, 14.72 moles of NaBr will produce = of calcium bromide

Hence, 7.36 moles of will be produced.

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