Xcc of 5N HCL was diluted to 1 litre of normal solution calculate the value of x​

200cc of 5N HCl were diluted

Explanation:n

Assuming the solution was diluted to prepare a 1N HCl solution:

The HCl was diluted from 5N to 1N, that is a dilution of:

5N / 1N = 5 times

As the total volume of the diluted solution is 1L = 1000mL = 1000cc the amount of the concentrated solution was:

1000cc / 5 =

the answer is b. dilution

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante