HI(aq)+H2O(l)→ H3O+(aq)+I−(aq) Match the words to the appropriate blanks in the below sentences.

a. The Bronsted-Lowry ace is :
b. The Bronsted-Lowry base is :
c. The conjugate acid is :
d. The conjugate base is:

1. H2O(l)
2. HI(aq)
3. I^-
4. H2O^+

Given chemical reaction is:

HI(aq)+H2O(l)→ H3O+(aq)+I−(aq)

a. The Bronsted-Lowry ace is :

b. The Bronsted-Lowry base is :

c. The conjugate acid is :

d. The conjugate base is:

Explanation:

According to Bronsted-Lowry acid-base theory,

an acid is a substance, that is a proton donor.

A base is a proton acceptor.

The conjugate acid is formed from the base after gaining a proton.

The conjugate base is formed from the acid after losing a proton.

For the given reaction,

a. The Bronsted-Lowry acid is :__HI(aq)

b. The Bronsted-Lowry base is :_H2O(l)

c. The conjugate acid is :___H3O+(aq)

d. The conjugate base is:___I-(aq).

Explanation:

Bronsted -Lawry acid are hydrogen ion donators . Here HI  is Bronsted -Lawry acid.

HI   ⇄    H⁺   +   I⁻

Bronsted -Lawry base are those which can accept hydrogen ion .

I⁻  +  H⁺  ⇄   HI .

Conjugate acid -base pair are shown below .

          H₃O⁺        =        H⁺       +          H₂O .

conjugate acid                                    conjugate base .

( strong acid )                                       ( weak base )

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

i believe the answer is three water molecules