At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate c.

The value of for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

I:             0.700

C:              -2x           +2x           x

E:           0.700-2x      2x            x

Equilibrium moles of = x = 0.180 moles

Equilibrium moles of = 2x =

Equilibrium moles of = 0.700 - 2x =

Molarity is calculated by using the equation:

So,

The expression of for above equation follows:

Plugging values in above expression:

Hence, the value of for the given chemical equation is 0.0457.