Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

The question is incomplete, the complete question is:

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

(a): Calculate the grams of in 10.58 L of nitrogen gas

(b): Calculate the grams of in moles of nitrogen gas

(c): Calculate the moles of molecules in 3.94 grams of nitrogen gas

(d): Calculate the moles of molecules in 4.73 L of nitrogen gas

The correct options are (b) and (c).

Explanation:

We are given:

Molar mass of = 28.02 g/mol

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

At STP conditions:

1 mole of gas occupies 22.4 L of volume

For the given options:

(a): Volume is given and to calculate the mass of , we need to use both the conversion factors above.

The equation formed will be:

Mass of =

(b): Moles are given and to calculate the mass of , we need only the first conversion factor.

The equation formed will be:

Mass of =

(c): Mass is given and to calculate the moles of molecules, we need only the first conversion factor.

The equation formed will be:

Moles of molecules =

(d): Volume is given and to calculate the moles of molecules, we need only the second conversion factor.

The equation formed will be:

Moles of molecules =

Hence, the correct option is (b) and (c)

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