What weight of barium chloride will react with 2.36g of sodium sulphate in solution so as to produce 3.88g of barium sulphate and 1.94g of sodium chloride in solution? PLEASE give the answer faster ​

3.46 g of BaCl2

Explanation:

The equation of the reaction is;

BaCl2(aq) + Na2SO4(aq) > 2NaCl(aq) + BaSO4(s)

Number of moles of barium sulphate produced = 3.88 g/233.38 g/mol = 0.0166 moles

From the reaction equation;

1 mole of BaCl2 yields 1 mole of barium sulphate

Hence 0.0166 moles of BaCl2 yields 0.0166 moles of barium sulphate

Hence;

Mass of BaCl2 required = 0.0166 moles × 208.23 g/mol = 3.46 g of BaCl2

out of these options:

ability to burn paper

pure sodium reacting violently with water

the boiling point of water

helium does not tend to react with anything

i would say this is a physical property:

helium does not tend to react with anything

why? :

i said helium does not tend to react with anything because well, it reacts to ! but ability to burn paper, pure sodium reacting violently with water, & the boiling point of water are chemical or

physical properties: the properties of a substance that can be observed without changing the chemical makeup of the substance

chemical properties: properties of a substance relating to the chemical nature and reactivity of the substance

the volume increases