Gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield? A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%

( it’s not “D” because I got it wrong lol) pls help tho

% yield = 200%

Explanation:

By using 145 gram of aluminium

Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced

Using 145 grams of aluminium, the yield of Aluminium oxide  would have been = (101.96 g/mol/26.982 g/mol)/145 grams

= 547.9282485 gram

Now % yield = actual yield /theoretical yield * 100

Substituting the given values, we get -

% yield = (547.928/270) *100

% yield = 200%

at the bottom

explanation: