A rigid 4.50 L vessel contains 0.134 mol H2(g) at 28oC. A lab technician adds 0.092 mol F2(g), and a reaction proceeds where HF(g) is formed. a. What is the balanced equation for the reaction that occurred in the vessel?
b. What is the limiting reactant?
c. How many moles of each gas are there after the reaction is complete? Assume the reaction goes to completion. (Hint: Use an ICE chart)d. Find the partial pressure of each gas after the reaction?
e. What is the total pressure in the vessel after the reaction?

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters

Bis the answer to the question