The impurities like iron oxides and titanium(IV)oxide remain unaffected by the base and are filtered off. Why are they not affected?​

Ithink 2 is the correct

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj