6 a 100 sample of Au - 198 Au 198 be? Decays to 3.125 g in 13.5 days, what would the half-life of au198 be?

Half-life = 2.7 days

Explanation:

The radioactive decay of an isotope follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] could be taken as the amount of A after t time, k is decay constant, [A]₀ initial amount of A.

Replacing to solve k:

Ln[3.125g] = -k*13.5days + ln[100g]

-3.465736 = -k*13.5days

k = 0.2567days⁻¹

Half-life is:

half-life = ln2 / k

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