If 15 ml of water is added to a solution of hydrochloric acid with a pH of 2, how will the solution change?

pH of the solution will slightly increase as it becomes less acidic for which it turns out to be more diluted.

Explanation:

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In this case, according to the given information, it turns out possible for us to calculate the pH change of the solution by firstly calculating the HCl concentration, as equal to that of the hydrogen ions whose pH is 2 as this is a strong acid:

Now, since water is added to the solution, but we do not have the initial volume of this solution, we can ensure that its pH will increase, become less acidic, because the concentration of the acid, and consequently that of the hydrogen ions, is diminished as the volume is increased.

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1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: