How many moles of Fe(OH), are produced when 85.0 L of iron(III) sulfate at a concentration of 0.600 mol/L reacts with excess
NaOH?

102 mol Fe(OH)₃

Explanation:

The reaction that takes place is:

First we calculate how many Fe₂(SO₄)₃ moles reacted, using the given concentration and volume:

Then we convert Fe₂(SO₄)₃ moles into Fe(OH)₃ moles, using the stoichiometric coefficients of the reaction:

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→