The electron pair in a C-F bond could be considered Question 3 options: closer to C because carbon has a larger radius and thus exerts greater control over the shared electron pair closer to C because carbon has a lower electronegativity than fluorine an inadequate model since the bond is ionic centrally located directly between the C and F closer to F because fluorine has a higher electronegativity than carbon

closer to F because fluorine has a higher electronegativity than carbon

Explanation:

Electronegativity refers to the ability of an atom in a bonding situation to draw the shared electrons of the bond closer to itself.

Electronegativity increases across the period and decreases down the group. A highly electronegative atom draws the shared electron pair of a bond towards itself.

When two atoms are bonded together, the electron pair is always drawn closer to the atom that has a higher electronegativity.

Hence, the electron pair in a C-F bond could be considered closer to F because fluorine has a higher electronegativity than carbon.

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