An 18.7 g sample of platinum metal increases in temperature from 21.2C to 23.5C when 5.7 J of heat are added. What is the specific heat of platinum?

132.53 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁) Equation 1

Where Q = amount of heat, c = specific heat capacity of platinum metal, m = mass of platinum metal, t₁ = initial temperature, t₂ = Final temperature.

Make c the subeject of the equation

c = Q/m(t₂-t₁) Equation 2

From the question,

Given: Q = 5.7 J. m = 18.7 g = 0.0187 kg, t₁ = 21.2°C, t₂ = 23.5°C

Substitute these values into equation 2

c = 5.7/[0.0187×(23.5-21.2)]

c = 5.7/0.04301

c = 132.53 J/kg.°C

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