A sample of 4 liters of helium gas has a pressure of 800mmHg. What is the new pressure in mm of mercury when the volume is reduced to 1 Liter? (pls help!)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

answer: value for at is 1.61\times 10^{9}.

solution:

given:

since, hcn is an acid , as it gives hydronium ion in its solution.

for hcn

is a base which accepts of hydronium ions.

as the reaction has reversed the k' of the new reaction will be inverse of k of previous reaction.

since   is acting as a base so the value of will be :