How many formula units are in 25.4 g of MgCl2?

1.58 x

Explanation:

1 mole of magnesium chloride has a mass of 95.211 g and contains 6.022⋅formula units of magnesium chloride, you can say that,

25.0 g x (6.022 x form units MgCl2) /95.211 = 1.58 x

most likely he is cheating on you

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm