How many moles of NO are made from mixing 7.2 moles of NH3 and 9.6 moles
of O? Identify the limiting reagent.

216 g of NO

Explanation:

We begin from the reaction:

4NH₃ + 5O₂ →  4NO  + 6H₂O

We determine the limiting reactant with the moles of each reactant:

4 moles of ammonia react to 5 moles of oxygen

Our 7.2 moles of ammonia may react to (7.2 . 5) /4 = 9 moles

It's ok because we have 9.6 moles of oxygen. 0.6 moles still remain.

5 moles of oxygen react to 4 moles of NH₃

Our 9.6 moles of oxygen may react to (9.6 . 4) /5 = 7.68 moles

We only have 7.2 moles of NH₃ and we need 7.68; so there is no enough ammonia and that's our limiting reagent.

Now we determine the moles of product.

4 moles of ammonia can produce 4 moles of NO

Definetely our 7.2 moles, will produce 7.2 moles of oxide.

We convert to mass: 7.2 mol . 30 g/mol = 216 g

i believe it is a.) released into

explanation:

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.