Consider the following reaction: 2CuCl2 + 4KI → 2CuI + 4KCl + I2

When 0.64 grams of CuCl2 reacts with 0.78 grams of KI, how many grams of I2 are formed?

What is the limiting reactant?

What is the excess reactant?
PLEASE I NEED HELP

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