Select the structure that corresponds to the molecule name:

Option B

Explanation:

The name of the molecule is;

1,1,1,3,3,3-Hexachloropropanone

Now, we can see that it contains propanone which is also called acetone. So it will have a double bond with Carbon(C) and Oxygen (O).

Option B has that double bond between C and O that indicates it propanone or acetone.

Thus, it is the correct option.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.