Balance the equation​

The coefficients are: 1, 2, 1, 2

Explanation:

To know which option is correct, we shall balance the equation. This can be obtained as follow:

SnO₂ + H₂ —> Sn + H₂O

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

SnO₂ + H₂ —> Sn + 2H₂O

There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:

SnO₂ + 2H₂ —> Sn + 2H₂O

Now the equation is balanced.

The coefficients are: 1, 2, 1, 2

Thus, none of the options are correct.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%