Calculate what volume of the following solutions is required to obtain 0.280 mol of each solute. (a) 0.201 M AlCl3 L
(b) 3.48 M HCl L

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

the answer is alpha particles hope i you

56 moles of   lieter in chemistry

you gotta add the following molecules so we can give u an answer

explanation: