If 70 grams of sodium carbonate is used in the reactants. What VOLUME of CARBON DIOXIDE will be in the products. PLEASE HELP ​

Acids react with carbonates to liberate CO2.

You didn't mention the acid in question.,.

So I'll just pick for myself(HCl) and react with Sodium carbonate

The Equation of reaction would be

2HCl + Na2CO3 2NaCl + H2O + CO2

It is balanced

Explanation:

Given 70g of Sodium carbonate.

Reacting Moles of Na2CO3 = mass/molar mass

Molar Mass of Na2CO3 = 23x2 + 12 + 16x3 =106gmol-¹

Mole = 70/106

= 0.66 moles of Sodium Carbonate (Na2CO3)

Looking at our balanced equation...

1 Mole of Na2CO3 reacts to produce 1mole of CO2

Since Their Mole ratio is equal(1:1)...

It now means that an equal amount of CO2 will be produced

Therefore 0.66moles of Na2CO3 Will produce 0.66moles of CO2

So we now have moles of CO2

Recall ... 1mole of any gas at STP contains 22.4L

Therefore ...

0.66moles will contain

= 0.66 x 22.4L

=14.784L of CO2 will be in the products