A balloon with a volume of 2.0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1.0 atm. How does the volume of the balloon change after moving it to the hot room? ✔ It increases. What is the final volume of the balloon after it has been placed in the hot room?

The volume increases,

Final volume is 2.1L

Explanation:

Based on Boyle's law, the absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V1T2 = V2T1

Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing:

V1 = 2.0L

T2 = 35°C + 273.15 = 308.15K

V2 = ?

T1 = 25°C + 273.15 = 298.15K

2.0L*308.15K = V2*298.15K

2.1L = V2

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

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