If 4.00 moles of gasoline are burned according to the chemical reaction below, what volume of oxygen at STP is needed for complete
combustion?
2C2H18(I) + 25O2(g) → 16CO2(g) +18H2O(g)

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The volume of oxygen at STP is needed for complete given combustion is 1121.28 L.

Explanation:

The given reaction equation is as follows.

This shows that 2 moles of gasoline requires 25 moles of . Hence, moles of oxygen required to react with 4 moles of gasoline are calculated as follows.

At STP, the pressure is 1 atm and temperature is 273.15 K. Therefore, using ideal gas equation the volume of oxygen is calculated.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

Thus, we can conclude that volume of oxygen at STP is needed for complete given combustion is 1121.28 L.

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explanation:

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