Consider the reaction below. 2 upper I superscript minus (a q) plus upper C l subscript 2 (g) right arrow 2 upper C l minus (a q) plus upper I subscript 2 (a q).

Which half reaction correctly describes the reduction that is taking place?
Upper C l subscript 2 9 g) plus e superscript minus right arrow 2 upper C l superscript minu (a).
Upper C l subscript 2 (g) plus e superscript minus right arrow 2 upper C l superscript minus (a q).
2 upper I superscript minus (a q) right arrow upper I subscript 2 (a q) plus 2 e subscript minus.
2 upper I superscript minus (a q) right arrow upper I subscript 2 (a q) plus e superscript minus.

2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)

Explanation:

Let's consider the following balanced redox equation.

2 I⁻(aq) + Cl₂(g) → 2 Cl⁻(aq) + I₂(aq)

We can identify 2 half-reactions:

Oxidation: 2 I⁻(aq) → I₂(aq) + 2 e⁻

Reduction: 2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)

We can identify the second half-reaction as the reduction reaction because Cl₂ gains 2 electrons and its oxidation number decreases from 0 to 1-.

i'm assuming that it's c.) red bank..

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.