During an experiment, the percent yield of calcium chloride from a reaction was 85.22%. Theoretically, the expected amount should have been 113 grams. What was the actual yield from this reaction?
CaCO3 + HCI - CaCl2 + CO2 + H20
O 96.3 grams
О 99.0 grams
O 113 grams
O 121 grams

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

i need mutiple choices

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d

2b2t

explanation:

2b2t