Density measurements can be used to analyze mixtures. For example, the density of solid sand (without air spaces) is about 2.84 g/mL. The density of gold is 19.3 g/mL. If a 1.00 kg sample of sand containing some gold has a density of 3.10 g/mL (without air spaces), what is the percentage of gold in the sample

Following are the responses to the given question:

Explanation:

Let S = solid sandy mass inside the blend

Let G = gold mass in such a blend

We search that percent G by mass

Mixture density = total blend mass / total blend volume = 3.10 g/mL

Mixture sum

Complete mixing volume = sand volume + gold volume volume

Complete mixing volume

Total mixture volume:

When

Solving equation:

When  

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.