Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.

The total energy absorbed is 32.171 kilojoules.

Explanation:

The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:

(1)

Where:

- Mass of the ice, in kilograms.

- Specific heat of ice, in kilojoules per kilogram-degree Celsius.

- Specific heat of water, in kilojoules per kilogram-degree Celsius.

- Latent heat of fusion, in kilojoules per degree Celsius.

- Initial temperature of water, in degrees Celsius.

- Fusion point of water, in degrees Celsius.

- Final temperature of water, in degree Celsius.

- Total energy absorbed, in kilojoules.

If we know that , , , , , and , then the total energy absorbed is:

The total energy absorbed is 32.171 kilojoules.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.