How much heat is required to raise the temperature of a sample of copper from 0.0°C to 55.0°C, if its specific heat is 0.384 J/g°C and its mass is 10.00 g? Group of answer choices 351.4 2110 211.2 3.54

211.2 J

Explanation:

Applying

Q = cm(t₁-t₂) Equation 1

Where Q = Amount of heat, c = specific heat capacity of copper, m = mass of copper, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: c = 0.384 J/g°C, m = 10 g, t₁ = 0°C, t₂ = 55°C

Substitute these value into equation 1

Q = 0.384×10×(55-0)

Q = 0.384×10×55

Q = 211.2 J

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

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