Chemistry, 18.05.2021 07:10 blazenrais

Describe the process of making 1.0 L of a 0.03 M solution of cobalt (II) chloride from the solid state. Be sure to include all instrumentation and glassware.

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Answer from: mmagee2020

By measuring out 3.9 grams of cobalt (II) chloride up to a volume of 1.0 L of solution.

Explanation:

Hello there!

In this case, considering this question about molarity, it turns out possible for us to calculate the required mass of cobalt (II) chloride by firstly compute the moles present in 1.0L of the given 0.03-M solution:

$M=\frac{n}{V} \\n=V*M\\\\n=1.0L*0.03\frac{molCoCl_2}{L}\\\\n=0.03molCoCl_2$

Next, since the molar mass of cobalt (II) chloride is 129.84 g/mol, we compute the grams we need to measure out in order to prepare this solution:

$m_{CoCl_2}=0.03molCoCl_2*\frac{129.84gCoCl_2}{1molCoCl_2} \\\\m_{CoCl_2}=3.9gCoCl_2$

Regards!

Answer from: Quest

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

let g(n) be the amount of contaminants (in grams) that remained by the beginning of the nth hour. g is a sequence, what kind of sequence is it, arithmetic or geometric? then, write an explicit formula for the sequence, g(n)=

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

explanation:

Answer from: Quest

You know how the first one if filled up like the objects do the same but with the other categories

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