Calculate the moles of of Fe that would be needed to form 336 grams of Cl2 (round your answer to 2 decimals) 2Fe + 3Cl2 → 2FeCl3

6.32 moles of Fe

Explanation:

The given chemical equation is presented as follows;

2Fe + 3Cl₂ → 2FeCl₃

The mass of Cl₂ in the reaction = 336 grams

The molar mass of chlorine gas Cl₂ = 35.435 g/mol

The number of moles, n = Mass/(Molar mass)

The number of moles of Cl₂ in the reaction, n = 336 g/(35.435 g/mol) ≈ 9.842 moles

From the given reaction, 3 moles of Cl₂ react with 2 moles of Fe to produce 2 moles of FeCl₃

By the law of definite proportions, we have that 9.482 moles of Cl₂ will react with approximately 9.482 × 2/3 = 6.32 moles of Fe to produce approximately 6.32 moles of FeCl₃

Therefore, approximately 6.32 moles of Fe will be required to react with 336 grams of Cl₂.

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