What is the molarity of 125 mL of a 8.25 M NaCl solution that has been diluted to 750. mL? a) 11 400 M
b) 0.00138 M
c) 1380 M
d) 0.0202 M
e) 1.38 M​

1.375 M

Explanation:

Using the formula as follows;

C1V1 = C2V2

Where;

C1 = initial concentration/molarity (M)

V1 = initial volume (L)

C2 = final concentration/molarity (M)

V2 = final volume (L)

According to the information in this question;

C1 = 8.25 M

C2 = ?

V1 = 125 mL = 125/1000 = 0.125L

V2 = 750 mL = 750/1000 = 0.750L

Using C1V1 = C2V2

8.25 × 0.125 = C2 × 0.750

1.03125 = 0.750C2

C2 = 1.03125 ÷ 0.750

C2 = 1.375 M