HELP DUE RN

8778 J

Explanation:

We'll begin by calculating the change in the temperature of water. This can be obtained as follow:

Initial temperature (T₁) = 10 °C

Final temperature (T₂) = 85 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 85 – 10

ΔT = 75 °C

Finally, we shall determine the heat required to raise the temperature of the water. This can be obtained as illustrated below:

Mass (M) = 28 g

Change in temperature (ΔT) = 75 °C

Specific heat capacity (C) = 4.18 J/gºC

Heat (Q) required =?

Q = MCΔT

Q = 28 × 4.18 × 75

Q = 8778 J

Thus, the heat required to raise the temperature of the water is 8778 J

explanation:

0.07 g/cm³

1.37 g/cm³