What is the pressure of a car tire that had an initial pressure of 33.7 kPa but was heated from 98.4°C to 110.°C?

34752.6 Pa.

Explanation:

Applying,

P/T = P'/T' Equation 1

Where P = Initial Pressure, T = Initial Temperature, P' =  Final pressure, T' = Final temperature.

make P' the subject of the equation

P' = (PT'/T) Equation 2

From the question,

Given: P = 33.7 kPa = 33700 Pa, T = 98.4°C = (273+98.4) = 371.4 K, T' = (110+273) = 383 K

Substitute these values into equation 2

P' = (33700×383)/371.4

P' = 34752.6 Pa.

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

2b2t

explanation:

2b2t