Calculate what the specific heat capacity of an unknown metal is if 394) of heat were released when 15.0 grams of the substance at 96.0°C was
cooled to 28.0°C?
Formula Reminders
q = mCAT
q = mHvap
q = mHfus
1. 4.01 J/gºC
2. 5910 J/g°C
3. 0.387 J/g°C

The specific heat capacity of an unknown metal is .

Explanation:

Given: Heat energy = 394 J

Mass = 15 g

Initial temperature =

Final temperature =

Formula used is as follows.

where,

q = heat energy

m = mass of substance

C = specific heat capacity

= initial temperature

= final temperature

Substitute the values into above formula as follows.

Thus, we can conclude that the specific heat capacity of an unknown metal is .

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.