If 53.0 g Na2CO3 is dissolved in enough water to make 500 mL of solution, what is the molarity of this solution?
(1 Mole of Na2CO3 = 106 g).
a. 2.0 M
b. 1.0 M
c. 1.5 M
d. 0.5 M

the link still does not work even when adding it to the url bar

explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

a is the correct answer

answersilicon (si); oxygen (o);