Complete combustion of 1 mol of propane (C3H8) liberates -2044 kJ/mol: C3H8(g) + 5O2 → 3 CO2(g) + 4H2O
Using this information together with the standard enthalpies of formation given below, calculate the standard enthalpy of formation of propane.
CO2(g)= -393.5 kJ/mol
O2 = 0 kJ/mol
H2O = -284 kJ/mol

A) -568 kJ/mol
B) -418 kJ/mol
C) -272.5 kJ/mol
D) 150 kJ/mol