Dalton’s Law PT = P1 + P2 + P3
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Dalton’s Law PT = P1 + P2 + P3
Jenny has three containers which each has a volume of 2 liters. The first container has a pressure of 1.2 atms, the second container has a pressure of 1.7 atms, and the third container has an unknown pressure. She puts the three gases into a two-liter container and records the total pressure to be 3.5 atms. What was the pressure of the third container?
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Be sure to answer all parts. the following equilibrium constants were determined at 1123 k: c(s) + co2(g) ⇌ 2co(g) k'p = 1.30 × 1014 co(g) + cl2(g) ⇌ cocl2(g) k''p = 6.00 × 10−3 calculate the equilibrium constant at 1123 k for the reaction: c(s) + co2(g) + 2cl2(g) ⇌ 2cocl2(g) 4.68 × 10 9 (enter your answer in scientific notation.) write the equilibrium constant expression, kp:
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Dalton’s Law PT = P1 + P2 + P3
Dalton’s Law PT = P1 + P2 + P3
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