50.0 grams of ammonium phosphate reacted with 44.0 grams of iron(II) chloride. Calculate the theoretical yield of iron(II) phosphate. What is the percent yield if 36.9 g was recovered from the reaction in lab? 2 (NH4)3PO4 + 3 FeCl2 Fe3(PO4)2 + 6 NH4Cl

catya your not at all which answer i've seen you do this on another question!

може ли да зареждате повече информация, моля

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied