In a 1.0L vessel at 1000K, 0.250 mol SO2(g) and 0.200 mol O2(g) react to form 0.162 mol SO3 at equilibrium. What is the Kc at 1000K for this reaction? 2SO2(g) + O2(g) <-> 2SO3(g) (balanced equation)

This problem is supposed to be solved using an ICE table.

Plz help me I have no idea how to use ICE tables

i'm pretty sure it is letter c.) car

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied